If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+4+13x=0
a = 4; b = 13; c = +4;
Δ = b2-4ac
Δ = 132-4·4·4
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{105}}{2*4}=\frac{-13-\sqrt{105}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{105}}{2*4}=\frac{-13+\sqrt{105}}{8} $
| R(x)=3x,C(x)=0.01x^2+0.3x+20 | | 3x-2=1x+12 | | 2(3)+3y-6=0 | | 8n+10=-102 | | 5/x=12/3 | | 3x-16=2x+7 | | (11x+7)(4x-7)=0 | | 6=8+8x | | 173=86-w | | x+(-96)=48 | | x-2+3=24 | | (1/3)y=1/5 | | -7x+4÷3+7/3=-7x÷5 | | 13x-5=4x+4 | | 8n+7-3n=88 | | 2x-15=1x+7 | | -10=(5+n)/3 | | x2=-3 | | -90=6p | | -3r+9=-4r=5 | | 1/5t+2-t=17 | | 3/5x+1/5=-2/5x-1/4 | | F(x)=x2+12x+18 | | -5=(r/20)-5 | | 66+66+2y=360 | | 3/4=24/4-1/2x+-2=12/8-3/8x-2/8 | | 7x+46=9x+34 | | a=170+-2a | | 23x+9=82x+1 | | 11+3e=2e+19 | | -21=-6x+3(x-3) | | 12x^2+3x+54=180 |